Question

2n = 64, then find the values of 2n+2 and 2n-2.​

Answer 1

Answer:

given, 2n = 64

n = 64/2 = 32

putting value of n in the equations.

2n + 2 = 2(32) + 2

= 64 + 2 = 66

2n - 2 = 2(32) - 2

= 64 - 2

= 62

Answer 2

$\displaystyle \sf{ {2}^{n + 2} = 256 \: \: and \: \: {2}^{n - 2} = 16 }$

Correct question :

$\displaystyle \sf{ {2}^{n } = 64 \: \: then \:find \:the \: values \: of \: \: {2}^{n + 2} \: \: and \: \: {2}^{n - 2} }$

Given :

$\displaystyle \sf{ {2}^{n } = 64 }$

To find :

$\displaystyle \sf{ {2}^{n + 2} \: \: and \: \: {2}^{n - 2} }$

Solution :

Step 1 of 2 :

Find the value of n

$\displaystyle \sf{ {2}^{n } = 64 }$

$\displaystyle \sf{ \implies {2}^{n } = {2}^{6} }$

$\displaystyle \sf{ \implies n = 6 }$

Step 2 of 2 :

$\displaystyle \sf{Find \: the \: values \: of \: \: {2}^{n + 2} \: \: and \: \: {2}^{n - 2} }$

Now,

$\displaystyle \sf{ {2}^{n + 2} }$

$\displaystyle \sf{ = {2}^{6 + 2} }$

$\displaystyle \sf{ = {2}^{8} }$

$\displaystyle \sf{ = 256 }$

Again,

$\displaystyle \sf{ {2}^{n - 2} }$

$\displaystyle \sf{ = {2}^{6 - 2} }$

$\displaystyle \sf{ = {2}^{4} }$

$\displaystyle \sf{ = 16 }$

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