Question

(2n²-12n+8)÷2n quotient= and remainder​

Answer 1

Answer:

   82n−(62)2n+1

=(9−1)2n−(63−1)2n+1=(2nC092n−2nC192n−1+....+2nC2n90)−(2n+1C0(63)2n−2n+1C1(63)2n+....+2n+1C2n+1(63)0)=9k1+1+63k2+1=9(k1+7k2)+2=9(k3)+2

Hencve, 2 is the remainder.