2n²-3n+1 find the first five terms
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an = 2n²- 3n + 1
putting n = 1,
a1 = 2 - 3 + 1 = 0
put n = 2,
a2 = 8 - 6 + 1 = 3
put n = 3,
a3 = 18 - 9 + 1 = 10
put n = 4
a4 = 32 - 12 + 1 = 21
put n = 5 ,
a5 = 50 - 15 + 1 = 36
hence first five terms are; 0 , 3 , 10 , 21 & 36
putting n = 1,
a1 = 2 - 3 + 1 = 0
put n = 2,
a2 = 8 - 6 + 1 = 3
put n = 3,
a3 = 18 - 9 + 1 = 10
put n = 4
a4 = 32 - 12 + 1 = 21
put n = 5 ,
a5 = 50 - 15 + 1 = 36
hence first five terms are; 0 , 3 , 10 , 21 & 36
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