Math, asked by sonu3674, 1 year ago

2n²+5n-900=0. please solve

Answers

Answered by BORONTS
2
2 {n}^{2} + 5n - 900 = 0 \\ or. \: 2 {n}^{2} + (45 - 40)n - 900 = 0 \\ or. \: 2 {n}^{2} + 45n - 40n - 900 = 0 \\ or. \: n(2n + 45) - 20(2n + 45) = 0 \\ or \: (2n + 45)(n - 20) = 0 \\ as \: the \: product \: of \: two \: numbers \: cannot \: be \: zero \: \\ then \\ 2n + 45 = 0 \\ or. \: n = - \frac{45}{2} = - 22 \ \frac{1}{2} \\ and \: \: n - 20 = 0 \\ or. \: n = 20

sonu3674: wrong
BORONTS: what's wrong
sonu3674: 20(2n+45)
BORONTS: I can't understand,,, what's wrong
BORONTS: can you please elaborate
Answered by arjunfuke
0

Answer:

2n2+(45-40)n=2=0

2n2+45-40n-2=0

N(2n+45)-20(2n+45)=0

2n+45=0

N=-45/2=-22 1/2

And n-20=0

n=20

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