Question

2Na3PO4(aq) + 2CuCl2(aq) -> Cu3(PO4)2(s) + 6NaCl(aq) What volume of 0.175 M Na3PO4 solution is necessary to completely reacts with 95.4 mL of 0.102 M CuCl2?

Answer 1

Answer:

First find the moles of CuCl2 by using the molarity, M (mol/L)

(91.6 mL /(1000 mL/L)) = 0.0916 L  --> 0.0916L(0.106 mol/L) = 9.71 x 10-3 mol CuCl2

 

Then use the mole ratio 2:3 Na3PO4:CuCl2 from the equation to determine the number of moles of Na3PO4

9.71 x 10-3 mol CuCl2 (2 mol Na3PO4/3 mol CuCl2)

= 6.47 x 10-3 mol Na3PO4

 

And we know the molarity (mol/L) of the Na3PO4 solutions, so we solve for volume (V)

 

6.47 x 10-3 mol / V = 0.183 M = 0.183 mol/L

 V = 6.47 x 10-3 mol/(0.183 mol/L)--> the volume will be in liters