Question

2NaN3(s)→2Na(s)+3N2(g) Given the equation, how many moles of N2 are produced by the decomposition of 1.50 mol of NaN3?

Answer 1

Answer : The number of moles of nitrogen gas produced are, 2.25 moles.

Explanation : Given,

Moles of sodium azide = 1.50 mole

The given balanced chemical reaction is,

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

From the given balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3

As, 2 moles of sodium azide decomposes to give 3 moles of nitrogen gas

So, 1.50 moles of sodium azide decomposes to give $\frac{3}{2}\times 1.50=2.25$ moles of nitrogen gas

Therefore, the number of moles of nitrogen gas produced are, 2.25 moles.