Math, asked by MysticAnswerer, 1 year ago

2nd derivative of 3x³

Answers

Answered by HappiestWriter012
4
lets find first derivative




f¹(x)=3d/dx(x³)

by power rule d/dx(xⁿ) is nx^n-1

f¹(x)=3(3x^3-1)

=3(3x²)=9x²

f¹¹(x)=9d/dx(x²)

=9(2x^2-1)

=18x
Answered by Anonymous
2
Hey mate.....

here's Ur answer........

Ans))))) 2nd derivative of 3x^3 ......

f^1x = 3d/dx(x^3)

{By rule d/dx (x^n) is nx^n - 1}

f^1(x) = 3(3x^3 - 1)

3(3x)^2 = 9x^2

f^11(x) = 9d / dx (x^2)

9(2x^2-1)

=18x...

Hope it Helps

Be brainly.....
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