2nd derivative of 3x³
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Answered by
4
lets find first derivative
f¹(x)=3d/dx(x³)
by power rule d/dx(xⁿ) is nx^n-1
f¹(x)=3(3x^3-1)
=3(3x²)=9x²
f¹¹(x)=9d/dx(x²)
=9(2x^2-1)
=18x
f¹(x)=3d/dx(x³)
by power rule d/dx(xⁿ) is nx^n-1
f¹(x)=3(3x^3-1)
=3(3x²)=9x²
f¹¹(x)=9d/dx(x²)
=9(2x^2-1)
=18x
Answered by
2
Hey mate.....
here's Ur answer........
Ans))))) 2nd derivative of 3x^3 ......
f^1x = 3d/dx(x^3)
{By rule d/dx (x^n) is nx^n - 1}
f^1(x) = 3(3x^3 - 1)
3(3x)^2 = 9x^2
f^11(x) = 9d / dx (x^2)
9(2x^2-1)
=18x...
Hope it Helps
Be brainly.....
here's Ur answer........
Ans))))) 2nd derivative of 3x^3 ......
f^1x = 3d/dx(x^3)
{By rule d/dx (x^n) is nx^n - 1}
f^1(x) = 3(3x^3 - 1)
3(3x)^2 = 9x^2
f^11(x) = 9d / dx (x^2)
9(2x^2-1)
=18x...
Hope it Helps
Be brainly.....
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