Question

2nd derivative of (xy^3)/1+secy = 1+y^4​

Answer 1

Answer:

y

3

+

3

y

2

x

d

d

x

[

y

]

+

3

y

2

x

sec

(

y

)

d

d

x

[

y

]

+

y

3

sec

(

y

)

−

y

3

x

sec

(

y

)

tan

(

y

)

d

d

x

[

y

]