2nd kinematic equation derivation s =ut+1/2at^2 . prove it mathematically using graph
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Aim:Derive kinematic equation of derivatives s=ut+1/2at² by graphically
Solutions :As we know ,area under v-t graph = displacement(s)
s = area under graph AB
s = area of rectangleOCEA+area of triangleAEBs s =(OA×OC) + (1/2×AE×BE).........(1)
from the figure show in the picture ,we considered,,
OA =u
OC=t
AE=OC=t
andBE=at
(((((((((as we know ,slope of v-t curve =tanΦ= =acceleration
(,,a=BE
AE
a=BE
t
BE=at))))))))
substitute these values in (1) experiment
s=ut+1/2(t)(at)
s= ut+1/2at²
hence derived✨
please mark it as brainliest answer ✨
may it helps u
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