2nd one is the question
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Answer:
b²-2ac/a²
Step-by-step explanation:
Sum of roots= -b/a
product of roots taken two at a time
= c/a
alpha² + beta² + gama² = (alpha+beta+gama)² - 2(alpha×beta + beta×gama + gama×alpha)
= b²/a² - 2c/a = (b²- 2ac)/a²
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(b^2-2ac)/a^2 is ur ans
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