2nd question An open tank with inner dimensions 80cm*75cm*120cm is to be cemented find the weight of cement required if 300g of cement is used to cement 15cmsq of area .
Answers
The weight of cement required if 300 g of cement is used to cement 15 cm sq of area is 864000 g.
Step-by-step explanation:
The inner dimensions of the open tank:
Length, l = 80 cm
Breadth, b = 75 cm
Height, h = 120 cm
Since its an open tank so the cementing can be done only on the 4 walls and the base of the tank, therefore, we get
The area of the walls of the tank required to be cemented is given by,
= [Curved surface area of cuboidal tank] + [area of the base]
= [2h(l+b)] + [l×b]
= [2 × 120 × (80 + 75)] + [80 × 75]
= 37200 + 6000
= 43200 cm²
Now,
It is given that to cement 15 cm² of area 300 g of cement is used
Then, to cement 43200 cm² of area, the amount of cement required will be,
= × 43200
= 864000 g
Thus, the weight of the required cement is 864000 g.
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