Question

2nd question An open tank with inner dimensions 80cm*75cm*120cm is to be cemented find the weight of cement required if 300g of cement is used to cement 15cmsq of area .

Answer 1

The weight of cement required if 300 g of cement is used to cement 15 cm sq of area is 864000 g.

Step-by-step explanation:

The inner dimensions of the open tank:

Length, l = 80 cm

Breadth, b = 75 cm

Height, h = 120 cm

Since its an open tank so the cementing can be done only on the 4 walls and the base of the tank, therefore, we get

The area of the walls of the tank required to be cemented is given by,

= [Curved surface area of cuboidal tank] + [area of the base]

= [2h(l+b)] + [l×b]

= [2 × 120 × (80 + 75)] + [80 × 75]  

= 37200 + 6000

= 43200 cm²

Now,

It is given that to cement 15 cm² of area 300 g of cement is used

Then, to cement 43200 cm² of area, the amount of cement required will be,

= $\frac{300}{15}$ × 43200

= 864000 g

Thus, the weight of the required cement is 864000 g.

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