Question

2NH,(g) + 3C1,(g) → N.(g) + 6HCI(g)
(0) Calculate the volume of chlorine, measured at room temperature and pressure, needed to
react completely with 0.68g of ammonia.
volume of chlorine =
cm [3]

Answer 1

Answer:

1334cm3

Explanation:

2 moles of ammonia react with 3mole of cl

then o.68/17mole will react with 6/100mole

then 6/100×22400=1334cm3

Answer 2

To react completely with 0.68g of NH3 at room temperature and pressure 4480 cm³ Chlorine is needed.

Given:

$2NH_3+3Cl_2=N_2+6HCl$

The weight of ammonia = 0.68g

To Find:

The volume of chlorine, measured at room temperature and pressure, needed to react completely with 0.68g of ammonia.

Solution:

In the reaction, 2 moles of ammonia react with 3 moles of Chlorine.

2 moles of ammonia have a molecular mass of 34g.

3 moles of chlorine have a molecular mass of 105g.

34g ammonia reacts with 105g chlorine.

Therefore, 0.68g ammonia reacts with $\frac{105*0.68}{34} =2.1$ g chlorine.

At STP,

35g Chlorine has a volume of 22.4 L.

Therefore, 2.1g Chlorine has volume of $\frac{22.4*2.1}{35} = 0.448$ L

0.448L is equal to 4480 cm³.

Hence, to react completely with 0.68g of NH3 at room temperature and pressure 4480 cm³ Chlorine is needed.

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