Question

2numbers less than third number by 30% and 37%.How much percent is first number greater than secind number

Answer 1

$\:\:\:\: \: \: \: \: \: \: \: \: \: \: \large\mathfrak{\underline{\underline{\huge\mathcal{\bf{\boxed{\huge\mathcal{~~QUESTION~~}}}}}}}$

2numbers less than third number by 30% and 37%.How much percent is first number greater than secind number

$\:\:\:\: \: \: \: \: \: \: \: \: \: \: \large\mathfrak{\underline{\underline{\huge\mathcal{\bf{\boxed{\huge\mathcal{!!ANSWER!!}}}}}}}$

$\:\:\:\: \: \: \: \: \: \: \: \: \: \: \large\mathfrak{\large\mathcal{\bf{\boxed{\large\mathcal{\:42.86 percent\:and58.73 percent}}}}}$

$\:\: \underline{\underline{\bf{\large\mathfrak{~~solution~~}}}}$

let the numbers are X and y

and the third is z

now..for the first case....

$x = z(1 - \frac{30}{100} \\ = > x = \frac{70z}{100} \\ = > x = \frac{7z}{10}$

and for the second case....

$y = z(1 - \frac{37}{100} ) \\ = > y = \frac{63z}{100}$

now the first number is less than of z by

=1-(70z/100)

=3z/10

therefore % is

$= \frac{ \frac{30z}{10} }{ \frac{70z}{100} } \times 100 \\ = \frac{300}{7} \: \: percent \\ = 42.86 \: \: percent$

and the second number is less than by

=37z/100

therefore% is

$= \frac{ \frac{37z}{100} }{ \frac{63z}{100} } \times 100 \\ = \frac{3700}{63} \\ 58.73 \: \: percent$

$\huge\mathcal\green{\underline{hope\:\: this\:\: helps\:\: you}}$