Question

(2p-1/2p)3
$(a - b)^{3} = {a}^{3} - 3 \times {a}^{2} \times b +3 \times a \times{b}^{2} - {b}^{3}$
solve by using this formula
correct answer will be marked as brainlist​

Answer 1

Step-by-step explanation:

$(2p - \frac{1}{2p} ) {}^{3} = {(2p)}^{3} - 3 \times {(2p)}^{2} \times \frac{1}{2p} + 3 \times 2p \times {( \frac{1}{2p} )}^{2} - ( \frac{1}{2p} ) {}^{3}$

$= 8 {p}^{3} - 6p + 3p \times \frac{1}{2p} - \frac{1}{8 {p}^{3} }$

$= 8 {p}^{3} - 3p \times \frac{1}{2p} - \frac{1}{8 {p}^{3} }$