Question

(2p-1)x+(p-1)y=2p+1,y+3x-1=0find p

Answer 1

Answer:

Step-by-step explanation:

from equation[2],we have y == [1--3x]  

we substitute this value of y in equation[1]  

(2p-1)x + (p-1)[1--3x] = 2 p+1.  

2px -- x + p --1 --3x[p --1]= 2p +1  

x[2p --1--3p+3]= 2p+1--p +1  

x[2--p]=[2 +p];  

x=[ 2+p]/[2--p]...........[3]  

hence  

y=1--3[2+p]/[2-p]==[2--p--6--3p]/[2--p...  

y= [ --4--4p]/[2--p]  

y=[4(p+1)]/[p-2]

hope it helps