Question

(2p^2 + 2p)-(-p^2 + 2p)=?​

Answer 1

Answer:

Here's your answer

Step-by-step explanation:

Given (p

2

−2p+1)x

2

−(p

2

−3p+2)x+(p

2

−1)=0

(p−1)

2

x

2

−(p−1)(p−2)x+(p−1)(p+1)=0

(p−1)((p−1)x

2

−(p−2)x+(p+1))=0

Given (p

2

−2p+1)x

2

−(p

2

−3p+2)x+(p

2

−1)=0 has more than two roots

since a quadratic equation has maximum of two roots So it means the above equation should be correct for all values of x

⟹p−1=0⟹p=1

Hope it helps

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Answer 2

:⟼  $( {2 p}^{2} + 2p) - ( - {p}^{2} + 2p)$

Remove parenthesis.

:⟼  $2 {p}^{2} + 2p + {p}^{2} - 2p$

Collect like terms.

:⟼  $(2 {p}^{2} + {p}^{2} ) +( 2p - 2p)$

:⟼  $3 {p}^{2} + 0$

:⟼  $\bigstar \: \boxed{\sf{\color{red}{3 {p}^{2} }}}$