(2p+2m+4n)²
![(2p + 2m + 4n) (2p + 2m + 4n)](https://tex.z-dn.net/?f=%282p+%2B+2m+%2B+4n%29)
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Answer:
⇔(2p + 2m + 4n)²
⇔ 2p² + 2m² + 4n² is answer
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