Question

2p^3 - 3p + 1 + 6 - 4p^2 - 5 p​

Answer 1

Answer:

Given that:

2p

4

−3p

3

+p

2

−5p+7&−3p

4

−7p

3

−3p

2

−p−12

now add both of them,

=(2p

4

−3p

3

+p

2

−5p+7)+(−3p

4

−7p

3

−3p

2

−p−12)

=(2p

4

+(−3p

4

))+((−3p

3

)+(−7p

3

))+((p

2

)+(−3p

2

))+(−5p−p)+(7−12)

=−p

4

−10p

3

−2p

2

−6p−5

Answer 2

Answer:

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Step-by-step explanation:

Explanation:

(2p^3+5p^2-4)(3p+1)=2p^3xx3p+5p^2xx3p-4xx3p+2p^3+5p^2-4

=6p^4+15p^3-12p+2p^3+5p^2-4

(2p^3+5p^2-4)(3p+1)=6p^4+17p^3+5p^2-12p-4