Question

(2p+3m+4n)² pls help I will rate u ​

Answer 1

=>(2p+3m+4n)²

We know that---------- (a+b+c)²=a²+b²+c²+2ab+2bc+2ca

=>(2p)²+(3m)²+(4n)²+2×2p×3m+2×3m×4n+2×4n×2p

=>4p²+9m²+16n²+12pm+24mn+16np

Answer 2

Answer:

9m^2+24mn+12mp+16n^2+16np+4p^2

Step-by-step explanation:

(2p+3m+4n)^2

=(2p+3m+4n)(2p+3m+4n)

=(2p)(2p)+(2p)(3m)+(2p)(4n)+(3m)(2p)+(3m)(3m)+(3m)(4n)+(4n)(2p)+(4n)(3m)+(4n)(4n)

=4p^2+6mp+8np+6mp+9m^2+12mn+8np+12mn+16n^2

=9m^2+24mn+12mp+16n^2+16np+4p^2

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