Math, asked by gauravy7310, 5 months ago

(2p+3q)³-(2p-3q)³ factorise

Answers

Answered by varad032005

2

Answer:

Step-by-step explanation:

(2p+3q)³ -(2p-3q)³ [a³-b³ = (a-b)(a²+ab+b²)]

(2p+3q-2p+3q)[(2p+3q)² + (2p+3q)(2p-3q) + (2p-3q)²]

(6q)(4p²+9q²+12pq + 4p²-9q² +4p²+9q²-12pq)

(6q)(12p²+9q²)

9(2q)(4p² + 3p²)

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