Question

(2p-3q) (4p² +6pq+9q²)+(3p-2q)(9p²+6pq+4q²)solve this question plzz​

Answer 1

Answer:

1pq+1p3q3+1pq+1p3q3

Answer 2

Answer:

35p^3-35q^3

Step-by-step explanation:

Formula: a^3-b^3=(a-b)(a^2+b^2+ab)

In this case, (2p-3q) (4p² +6pq+9q²) become (2p)^3-(3q)^3 and (3p-2q)(9p²+6pq+4q²) become (3p)^3-(2q)^3

$(2p)^3-(3q)^3+(3p)^3-(2q)^3$

$8p^3+27p^3-27q^3-8q^3$

$35p^3-35q^3$