Question

2p+\dfrac{1}{3}2p+ 3 1 ​ 2, p, plus, start fraction, 1, divided by, 3, end fraction, -p+3−p+3minus, p, plus, 3, and 2p-\dfrac{1}{3}2p− 3 1 ​ 2, p, minus, start fraction, 1, divided by, 3, end fraction are consecutive terms of an arithmetic progression. Find the value of p​

Answer 1

Answer:

${ { {0 = + }^{2} }^{2} }^{2} { {2 {?}^{2} }^{2} }^{?} |222 - \div { = }^{2} \times \frac{?}{?} |$

10 {0 {53 { \frac{ \sqrt{ = = = = = = = { \frac{ \frac{ \frac{4 {5}^{2} }{?} }{?} }{?} }^{2} } }{?} }^{2} }^{2} }^{2}