Math, asked by rstiwari9685, 4 months ago

-2p+ q - 5pq - 13,1 - 3p - 10q + 2pq, 10pq - P​

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Answered by celljovi007
1

Step-by-step explanation:

Step-by-step explanation:Parameters

Step-by-step explanation:ParametersPopulation mean = μ = ( Σ Xi ) / N

Step-by-step explanation:ParametersPopulation mean = μ = ( Σ Xi ) / NPopulation standard deviation = σ = sqrt [ Σ ( Xi - μ )2 / N ]

Step-by-step explanation:ParametersPopulation mean = μ = ( Σ Xi ) / NPopulation standard deviation = σ = sqrt [ Σ ( Xi - μ )2 / N ]Population variance = σ2 = Σ ( Xi - μ )2 / N

Step-by-step explanation:ParametersPopulation mean = μ = ( Σ Xi ) / NPopulation standard deviation = σ = sqrt [ Σ ( Xi - μ )2 / N ]Population variance = σ2 = Σ ( Xi - μ )2 / NVariance of population proportion = σP2 = PQ / n

Step-by-step explanation:ParametersPopulation mean = μ = ( Σ Xi ) / NPopulation standard deviation = σ = sqrt [ Σ ( Xi - μ )2 / N ]Population variance = σ2 = Σ ( Xi - μ )2 / NVariance of population proportion = σP2 = PQ / nStandardized score = Z = (X - μ) / σ

Step-by-step explanation:ParametersPopulation mean = μ = ( Σ Xi ) / NPopulation standard deviation = σ = sqrt [ Σ ( Xi - μ )2 / N ]Population variance = σ2 = Σ ( Xi - μ )2 / NVariance of population proportion = σP2 = PQ / nStandardized score = Z = (X - μ) / σPopulation correlation coefficient = ρ = [ 1 / N ] * Σ { [ (Xi - μX) / σx ] * [ (Yi - μY) / σy ] }

Step-by-step explanation:ParametersPopulation mean = μ = ( Σ Xi ) / NPopulation standard deviation = σ = sqrt [ Σ ( Xi - μ )2 / N ]Population variance = σ2 = Σ ( Xi - μ )2 / NVariance of population proportion = σP2 = PQ / nStandardized score = Z = (X - μ) / σPopulation correlation coefficient = ρ = [ 1 / N ] * Σ { [ (Xi - μX) / σx ] * [ (Yi - μY) / σy ] }hlooooooo

Answered by babitarajput976916
3

Answer:

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Step-by-step explanation:

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