(2p² + 3q + 4 ) from (3p² + q)
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1
Answer:
hi the same as the information are in bus
Answered by
0
Answer:
Suppose (a+b) and (c−d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below.
(a+b)×(c−d)=a×(c−d)+b×(c−d)=(a×c−a×d)+(b×c−b×d)
=ac−ad+bc−bd
Let,
a=3p
2
,b=q
2
,c=2p
2
,d=3q
2
Now,
=3p
2
×(2p
2
−3q
2
)+q
2
×(2p
2
−3q
2
)
=[(3p
2
×2p
2
)+(3p
2
×−3q
2
)]+[(q
2
×2p
2
)+(q
2
×−3q
2
)]
=[6p
4
−9p
2
q
2
+2q
2
p
2
−3q
4
)]
=[6p
4
−7p
2
q
2
−3q
4
]
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