2p⁴+3p³-2p² what is factor
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Answered by
7
Now,
2p⁴ + 3p³ - 2p²
= p² (2p² + 3p - 2)
= p² (2p² + 4p - p - 2)
= p² {2p (p + 2) - 1 (p + 2)}
= p² (p + 2) (2p - 1),
which is the required factorization.
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Answered by
2
2p4 + (4-1) p3 - 2p2
2p4 + 4p3 -p3 - 2p2
2 p3 (p + 2 ) -p2 (p+2 )
(2p3 -p2 )(p+2)
p2 (2p -1)(p+2)
hope it jelps
2p4 + 4p3 -p3 - 2p2
2 p3 (p + 2 ) -p2 (p+2 )
(2p3 -p2 )(p+2)
p2 (2p -1)(p+2)
hope it jelps
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