Math, asked by Akhiltty1518, 1 day ago

2p5 – 3p4 – 4p3 + p2 – 6 by (p2 - 1)

Answers

Answered by nithya12333
1

Answer:

 {p}^{2}  - 1 =  0 \\  {p}^{2}  = 1 \\ p =  \sqrt{1 }  = 1 \\ 2 {p}^{5}  - 3 {p}^{4}  - 4 {p}^{3}  +  {p}^{2}  - 6 \\ =  2 - 3 - 4 + 1 - 6 \\  =  - 1 - 4 - 5 \\  =  - 10

Hope this may help you

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