Question

2power 35 is divisible by 5​

Answer 1

hey! friend...

here is ur answer

2^(4×8+3) ÷ 5 = 2^(4×8) ×2³ ÷ 5

= (16)^8 × 8 ÷ 5

16^8 ÷ 5 remainder is 1

8/5 remainder is 3

hope it helps u

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Answer 2

We can use cyclic remainder theorem.

2 ^1÷5=2

2^2÷5=4

2^3÷5=3

2^4÷5=1

2^5÷5=2

2^6÷5=4

•°• The power is 4

The remainder of 2^35÷5 will be ( 4k + n ) th

Now;

35 = 4*8+3 (k =8 , n = 3)

If n= 1 , r = 2

n=2 , r = 4

n= 3 , r = 3

n= 4 , r = 1

n = 5 , r = 2

n = 6 , r = 4


•°• remainder is 3

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