Question

2power x + 2power y =2 power x+y find dy /dx

Answer 1

Answer:

Step-by-step explanation:

2^x+2^y=2^x+y

(2^x)ln2 + (2^yln2)=(2^x+y)ln2(1+dy/dx)  (differentiation of LHS AND RHS)

dy/dx=(2^(x+y)-2^x)/(2^y-2^(x+y))       (bring all terms on one side and eliminating ln2)

or dy/dx=(2^x-y)(2^y -1 /1 - 2^x)

Answer 2

Answer:

Step-byf-step explanation:

Step by step