2power2x+1=4power2x-1
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brunoconti:
resend please. solution ready
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2^2x+1=4^2x-1
Lets find the solution other than finding coefficients
Take log on both sides
log (2^2x+1)=log(4^2x-1)
(2x+1)log2=(2x-1)log4
(2x+1)/2x-1 =log4/log2 [logm^n=nlogm]
(2x+1)/2x-1 =log2^2/log2
(2x+1)/2x-1=2log2/log2
(2x+1)/2x-1=2
2x+1=4x-2
2x+1-4x+2=0
-2x+3=0
x=3/2
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