Question

(2pq-q,) and (3p,+7q) ​

Answer 1

Answer:

Required sum =(p

2

−7pq−q

2

)+(−3p

2

−2pq+7q

2

)

Rearranging and collecting like terms

=p

2

−3p

2

−7pq−2pq−q

2

+7q

2

=−2p

2

−9pq−6q

2

Step-by-step explanation:

Subtracting 4p

2

q−3pq+5pq

2

−8p+7q−10 from 18−3p−11q+5pq−2pq

2

+5p

2

q, we have

= (18−3p−11q+5pq−2pq

2

+5p

2

q)−(4p

2

q−3pq+5pq

2

−8p+7q−10)

= 18−3p−11q+5pq−2pq

2

+5p

2

q−7p

2

q+3pq−5pq

2

+8p−7q+10

= 28+5p−78q+8pq−7pq

2

+p

2

q