Question

2px² - 6x - 3 = 0
For what value of p is this equation has real roots​

Answer 1

Answer:p=-3/2

Step-by-step explanation:

Given that equation has real roots ,

Therefore

Discriminant(D)=0

=>b^2-4ac=0

=>36-4(2p)(-3)=0

=>36+24p=0 =>36=-24p

=>p=-36/24 =>-3/2

I hope this answer will help you...