Question

( 2q +4 )^2

solve it by ( a+b )^2 formula​

Answer 1

Answer:-

$\\ \sf \longrightarrow \: (2q+4)^2$

We know that

$\boxed{\sf (a+b)^2=a^2+2ab+b^2}$

$\\ \sf \longrightarrow \: (2q+4)^2$

$\\ \sf \longrightarrow \: (2q)^2+2(2q)(4)+(4)^2$

$\\ \sf \longrightarrow \: 4q^2+4q(4)+16$

$\\ \sf \longrightarrow \: 4q^2+16q+16$

$\\ \therefore\sf (2q+4)^2=4q^2+16q+16$

Answer 2

4q² + 16q + 16.

Step-by-step explanation:

$(a + b {)}^{2} = {a}^{2} + 2ab + {b}^{2}$

$(2q + 4)^{2} = 2 {q}^{2} + 2 \times 2q\times4 \: + {4}^{2} .$

$= {4q}^{2} + 16q + 16.$