Question

(2r - 1) (2r +1) (4r2+1)

Answer 1

Answer:

Step-by-step explanation:

Answer:16r^4-1

Given that : (2r-1)(2r+1)(4r^2+1)

Now it can be written as [(2r-1)(2r+1)](4r^2+1)

first two terms are in the form of (a-b)(a+b)

we know that (a-b)(a+b)=a^2-b^2

now we have ,

[(2r)^2-(1)^2](4r^+1)

(4r^2-1)(4r^2+1)

again this is in the form of (a+b)(a-b)

so , we get (4r^2)^2-1^2= 16r^4-1

Answer 2

Answer:

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Answer:16r^4-1

Given that : (2r-1)(2r+1)(4r^2+1)

Now it can be written as [(2r-1)(2r+1)](4r^2+1)

first two terms are in the form of (a-b)(a+b)

we know that (a-b)(a+b)=a^2-b^2

now we have ,

[(2r)^2-(1)^2](4r^+1)

(4r^2-1)(4r^2+1)

again this is in the form of (a+b)(a-b)

so , we get (4r^2)^2-1^2= 16r^4-1

Step-by-step explanation:

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