Question

(2r – 5)^2 + (2r – 5)​

Answer 1

Answer: (2r – 5)² + (2r – 5)

= {(2r)²+(5)²-2(2r)(5)} +(2r-5)

= 4r²+25-20r +2r-5

= 4r²-18r+20

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