Math, asked by bhumikalights, 10 months ago

2root 3+3 whole divided by 2root 3-3

Answers

Answered by imsapna005
0

Answer:

this is your solution I hope your problem is solved

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Answered by mohitgurjar59
3

Answer:

 \sqrt[2]{3} + 3 \div  \sqrt[2]{3} - 3 \times  \sqrt[2]{3}  + 3 \div  \sqrt[2]{3}   +  3 \\ =( \sqrt[2]{3}  + 3)( \sqrt[2]{3}  + 3) \div ( { \sqrt[2]{3} }^{2}    - ( {3}^{2} ) \\= ( { \sqrt[2]{3} + 3 }^{2}  \div 12 - 9 \\ = { \sqrt[2]{3} }^{2} +  {3}^{2}  + 2( \sqrt[2]{3}(3) \div 3 \\= 12 + 3 +  \sqrt[6]{3}  \div 3 \\= 15  +  \sqrt[6]{3}  \div 3 \\= 3(5  +  \sqrt[2]{3})   \div 3 \\  = 5 +  \sqrt[2]{3}

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