Question

2root2acube+16root2bcube+c cube -12abc

Answer 1

2√2a³ + 16√2b³ + c³ - 12abc

a³ + b³ + c³ - 3abc = (a+b+c)(a²+b²+c² - ab - bc - ac)

(√2a)³ + (2√2b)² + c - 3(√2a)(2√2b)(c) = (√2a +2√2b + c) (2a² + 8b² +c² - 4ab - 2√2bc - 2√2ac)

I don't know what you are asking for. I hope it is what you want