Question

-2root2x = -3root2x + root2 ? anyone explain me how LHS and RHS is equal??? i am confused???? please do conference with me .... ​

Answer 1

$- 2 \sqrt{2x} = - 3 \sqrt{2x } + {\sqrt{2} } \\ = > - 2 \sqrt{2x} + 3 \sqrt{2x} = \sqrt{2 } \\ = > \sqrt{2x} = \sqrt{2} \\ = > \sqrt{2} \times \sqrt{x} = \sqrt{2} \\ = > \sqrt{x } = \frac{ \sqrt{2} }{ \sqrt{2 } } \\ = > \sqrt{x} = 1 \\ = > x = 1$

so it is possible when x = 1

Answer 2

Answer:

−2√2x =−3√2x + √2

=>−2√2x +3√2x = √2

=>2x = √2

=>√2 × √x = √2

=>√x = √2/√2

=>√x =1

=>x=1

so it is possible when x = 1....