Question

2root5+5root3-7root5+3root5-4root3
Plz answer if any one knows
It's for exam

Answer 1

Answer:

Step-by-step explanation:

2√5 + 5√3 -7√5 +3√5 -4√3

Combining like roots

2√5 -7√5 + 3√5 + 5√3 -4√3

-2√5 +√3

Or √3 -2√5

If you want to further solve it then our the values if √3 and √5 and get the answer.

Answer 2

Step-by-step explanation:

Given

$2\sqrt5+5\sqrt3-7\sqrt5+3\sqrt5-4\sqrt3\\ \\ \implies 5\sqrt5+\sqrt3-7\sqrt5\\ \\ \implies \bf \sqrt3-2\sqrt5\\ \\ \rm Now\ putting\ \sqrt3=1.732\ and\ \sqrt5=2.236\\ \\ \implies 1.732-2\times(2.236)\\ \\ \implies 1.732-4.472=-2.74\\ \\ \bf \therefore The\ value\ of\ 2\sqrt5+5\sqrt3-7\sqrt5+3\sqrt5-4\sqrt3\ is\ 2.74$