Math, asked by valaayush444, 4 days ago

2s² - ( 1 + 2√2 )s + √2 = 0 2s²- s - 2√2s + √2 = 0 s( 2s - 1 ) - √2( 2s - 1 ) = 0 ( s - √2 ) ( 2s - 1 ) = 0 s - √2 = 0 and 2s -1 = 0 s = √2 and s=\frac{1}{2}s= 2 1 ​ Therefore, Zeroe​

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Answered by diyapal339
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