2s²-(1+2√2)s+√2 plzz slove the question
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2s²-(1+2√2)s+√2=0
→2s²-s-2√2s+√2=0
→s(2s-1)-√2(2s-1)=0
→(s-√2)(2s-1)=0
Either s-√2=0 or 2s-1=0
s=√2 or s=1/2
→2s²-s-2√2s+√2=0
→s(2s-1)-√2(2s-1)=0
→(s-√2)(2s-1)=0
Either s-√2=0 or 2s-1=0
s=√2 or s=1/2
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