Question

2sec15° × cos 15°
please tell the answer ​

Answer 1

Answer:

$= \: 2 \times \sec(15) \times \cos(15) \\ = 2 \times \frac{1}{ \cos(15) } \times \cos(15) \\ [- - as \: \: secA \: = \frac{1}{cosA}] \\ \\ = \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2 \times 1 \\ \\ = \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \huge2$

so,

the required answer is —

2

Step-by-step explanation:

hope it's helpful,,,

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