Question

2sec2a= tanb + cotb then one of the value of a+b is...?

Answer 1

2sec2a  = tan b + cot b can be written as

 2sec2a = sinb/cosb + cosb/sinb

 2sec 2a = sin^2b+cos^2b/cosb*sinb   (sin^2theta+cos^2theta=1)

 2 sec 2a = 1/cosb*sinb

sec 2a = 1/2(cosb)(sinb)

1/cos2a = 1/sin2b

cos 2a = sin 2b.

2a + 2b = 90 degrees

2(a+b) = 90 degrees

a + b = 45 degrees.


Hope this helps!

Answer 2

Answer:

The answer is π/4 degrees