Question

2secA-(1+sinA)/cosA=....??

Answer 1

HELLO DEAR,

$2 \sec( \alpha ) - \frac{1 + \sin( \alpha ) }{ \cos( \alpha ) } \\ = > \frac{2}{ \cos( \alpha ) } - \frac{1 + \sin( \alpha ) }{ \cos( \alpha ) } \\ = > \frac{2 - 1 - \sin( \alpha ) }{ \cos( \alpha ) } \\ = > \frac{1 - \sin( \alpha ) }{ \cos( \alpha ) } \\ = > \frac{1}{ \cos( \alpha ) } - \frac{ \sin( \alpha ) }{ \cos( \alpha ) } \\ = > \sec( \alpha ) - \tan( \alpha )$
I HOPE ITS HELP YOU DEAR,
THANKS