Question

2sinθ − 1 = 0, find:

i) value of θ in degrees, when θ is an acute angle.

ii) cos2θ + tan2θ​

Answer 1

$\huge \red{answer}$

$\large\bold{given : 2sinθ - 1 = 0} \\ \\ \\ \large \bold{to \: find : \: value \: of \: θ \: and \: cos2(θ ) + tan2(θ ) }$

now sin2θ - 1 = 0

then sinθ = 1/2

as we know 1/2 = 30°

so θ = 30°

Therefore

cos2θ + tan2θ

from above θ = 30°

so cos2(30) + tan2(30)

ie cos60 + tan60

as we know cos60 = 1/2

and tan60 = √3

so

$\frac{1}{2} + \sqrt{3} = \frac{1 + 2 \sqrt{3} }{2}$

hope it helps you

be brainly