2sin^2( 45 - A) = 1 - sinA
Answers
Answered by
0
Answer:
2 sin square( 45°-A)
(therefore;
by trigonometry ratios
sin45°=1)
=2sin2(1-A)
=2sin(1-A)
=1+sin2A
hence proved
I HOPE THIS WILL HELP YOU
Answered by
1
Answer:
2sin²(45-A)=1-sinA
2Sin²45-2sin²A=1-sinA
2*1/4-2sin²A=1-sinA
1/2-1=2sin²A-sinA
-1/2=SinA(2SinA-1)
SinA=1/2
sin=1/4
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