Math, asked by namrata138pandey, 8 months ago

2sin^2( 45 - A) = 1 - sinA​

Answers

Answered by jmakima55
0

Answer:

2 sin square( 45°-A)

(therefore;

by trigonometry ratios

sin45°=1)

=2sin2(1-A)

=2sin(1-A)

=1+sin2A

hence proved

I HOPE THIS WILL HELP YOU

Answered by anubhavgupta357
1

Answer:

2sin²(45-A)=1-sinA

2Sin²45-2sin²A=1-sinA

2*1/4-2sin²A=1-sinA

1/2-1=2sin²A-sinA

-1/2=SinA(2SinA-1)

SinA=1/2

sin=1/4

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