Question

2sin^2 theta-1/sin theta×cos theta= 1-2 cos^2 theta/sin theta×cos theta​

Answer 1

Step-by-step explanation:

here's your answer...

Answer 2

Hi !

It's very easy chotu

Solution :-

From LHS :-

2sin²¢ -1 /cos¢ sin¢ = 2(1-cos²¢) -1/cos¢ sin¢

As we know that , sin²¢ = 1-cos²¢

= 2-2cos²¢ -1/cos¢sin¢

= 1-2cos²¢/cos¢ sin¢

here proved , LHS = RHS

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Hope it's helpful !