2sin^2x + root 3 Cosx+1 =
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is that +1 is in the root or not
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Thank you for asking this question:
2 sin² x + √3cos x + 1 = 0
2 (1-cos²x) + √3cos x + 1 = 0
2 cos² x - √3 cos x- 3 = 0
cos x = √3 +- √3 + 24/4
= √3 +- 3√3/4
cos x cannnot be greater than 1
cos x = - 2√3/4
= -√3/2
x = 2nπ +- 5π/6
If there is any confusion please leave a comment below.
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