Math, asked by srisayan5376, 10 months ago

2sin[(C+D)/2].sin[(D-C)/2] is equal to

A) cosC + cosD B) cosC - cosD C) sinC - sinD D) sinC + sinD

Answers

Answered by toorjaswinder92

1

Answer:

A.) cos C + cos D is correct answer

Answered by abduljaved68

4

Answer:

option a is the correct answer.

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