2sin square 30° -3cos square 45° +tan square 60°
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Answered by
91
2sin²30°-3cos²45°+tan²60°
=2×(1/2)²-3(1/√2)²+(√3)²
=(½)-(3/2)+(3)
= (-1)+(3)
=2
is the final answer
=2×(1/2)²-3(1/√2)²+(√3)²
=(½)-(3/2)+(3)
= (-1)+(3)
=2
is the final answer
Answered by
27
2sin ^230° - 3cos ^245°+ tan ^260°
2 × (1/2)^2 - 3×(1/root2)^2 + (root 3)^2
2× 1/4 - 3 ×1/2 + 3
1/2 - 3/2 + 3
= 1-3+6/2
= 4/2 = 2
2 × (1/2)^2 - 3×(1/root2)^2 + (root 3)^2
2× 1/4 - 3 ×1/2 + 3
1/2 - 3/2 + 3
= 1-3+6/2
= 4/2 = 2
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