Question

2sin theta + 3costheta = 2 prove 3sin theta - 2 cos theta = 3
Solve it fast ...plz​

Answer 1

Answer:

For my Comfort I take Theta as x

Step-by-step explanation:

1. 2sinx + 3cosx=4 (Given). Squarring both sides. (2sinx+3cosx)^²=2^². 4sin^²x+9cos^²+2(2sinx3cosx)=4 4(1-cos^²x) + 9(1-sin^²)+2(2sinx3cosx)=4 4cos^²x + 9sin^²x-2(2sinx3cosx)=4+9-4 by a²-b²formula we get a=2cosx,b=3sinx (2cosx - 3sinx)^²=9 Taking square root to other side 2cosx - 3sinx = + /- 3 Proved.